CN - VLSM Exercises

VLSM : EXERCISES

Exercise 3

We want to divide 192.168.10.0, which is a class C network, into four networks, each with unequal of IP address requirements as shown below:

·         Subnet A = 32 hosts

·         Subnet B = 8 hosts

·         Subnet C = 22 hosts

·         Subnet D = 60 hosts

Subnet D – 60 = 2⁶ = 64 – 2 = 62 hosts          S = 2²

Subnet A – 32 = 2⁶ = 64 – 2 = 62 hosts           S = 2²

Subnet C – 22 = 2⁵ = 32 – 2 = 30 hosts          S = 2³

Subnet B – 8 = 2⁴ = 16 – 2 = 14 hosts            S = 2⁴

Network Name	Network Address	Host Range	Broadcast Address	Subnet Mask
Subnet D	192.168.10.0	192.168.10.1 - 192.168.10.62	192.168.10.63	255.255.255.192
Subnet A	192.168.10.64	192.168.10.65 - 192.168.10.126	192.168.10.127	255.255.255.192
Subnet C	192.168.10.128	192.168.10.129 - 192.168.10.158	192.168.10.159	255.255.255.224
Subnet B	192.168.10.160	192.168.10.161 - 192.168.10.174	192.168.10.175	255.255.255.240

Exercise 4

Given a network of 201.4.3.0/24, subnet the network in order to create the subnetworks with the following requirements.

·         Office 1 – 14 host

·         Office 2 – 60 host

·         Office 3 – 32 host

·         Office 4 – 7 host

·         Office 5 – 15 host

Office 2 – 60 = 2⁶ = 64 – 2 = 62 hosts           S = 2²

Office 3 – 32 = 2⁶ = 64 – 2 = 62 hosts           S = 2²

Office 5 – 15 = 2⁵ = 32 – 2 = 30 hosts           S = 2³

Office 1 – 14 = 2⁴ = 16 – 2 = 14 hosts           S = 2⁴

Office 4 – 7 = 2⁴ = 16 – 2 = 14 hosts             S = 2⁴

Network Name	Network Address	Host Range	Broadcast Address	Subnet Mask
Office 2	201.4.3.0	201.4.3.1 - 201.4.3.62	201.4.3.63	255.255.255.192
Office 3	201.4.3.64	201.4.3.65 - 201.4.3.126	201.4.3.127	255.255.255.192
Office 5	201.4.3.128	201.4.3.129 - 201.4.3.158	201.4.3.159	255.255.255.224
Office 1	201.4.3.160	201.4.3.161 - 201.4.3.174	201.4.3.175	255.255.255.240
Office 4	201.4.3.176	201.4.3.177 - 201.4.3.190	201.4.3.191	255.255.255.240