CN - IP Subnetting - Class C xercise

1. You are given an IP Address of 192.168.10.0/26. Calculate how many subnets and host per subnet are available in this network. Create the table per this network.

Network Address	Valid Host Range	Broadcast Address	Subnet Mask
192.168.10.0	192.168.10.1 - 192.168.10.62	192.168.10.63	255.255.255.192
192.168.10.64	192.168.10.65 - 192.168.10.126	192.168.10.127	255.255.255.192
192.168.10.128	192.168.10.129 - 192.168.10.190	192.168.10.191	255.255.255.192
192.168.10.192	192.168.10.193 - 192.168.10.254	192.168.10.255	255.255.255.192

192.168.10.0/26

IIIIIIII IIIIIIII IIIIIIII II/IIIIII

Network = 2^2 = 4 networks

Hoat = 2^6 = 64 - 2 = hosts

2. You are given an IP Address of 223.14.3.0/28. Calculate how many subnets and host per subnet are available in this network. Create the table per this network.

Network Address	Valid Host Range	Broadcast Address	Subnet Mask
223.14.3.0	223.14.3.1 - 223.14.3.14	223.14.3.15	255.255.255.240
223.14.3.16	223.14.3.17 - 223.14.3.30	223.14.3.31	255.255.255.240
223.14.3.32	223.14.3.33 - 223.14.3.46	223.14.3.47	255.255.255.240
223.14.3.48	223.14.3.49 - 223.14.3.62	223.14.3.63	255.255.255.240
223.14.3.64	223.14.3.65 - 223.14.3.78	223.14.3.79	255.255.255.240
223.14.3.80	223.14.3.81 - 223.14.3.94	223.14.3.95	255.255.255.240
223.14.3.96	223.14.3.97 - 223.14.3.110	223.14.3.111	255.255.255.240
223.14.3.112	223.14.3.113 - 223.14.3.126	223.14.3.127	255.255.255.240
223.14.3.128	223.14.3.129 - 223.14.3.142	223.14.3.143	255.255.255.240
223.14.3.144	223.14.3.145 - 223.14.3.158	223.14.3.159	255.255.255.240
223.14.3.160	223.14.3.161 - 223.14.3.174	223.14.3.175	255.255.255.240
223.14.3.176	223.14.3.177 - 223.14.3.190	223.14.3.191	255.255.255.240
223.14.3.192	223.14.3.191 - 223.14.3.206	223.14.3.207	255.255.255.240
223.14.3.208	223.14.3.209 - 223.14.3.222	223.14.3.223	255.255.255.240
223.14.3.224	223.14.3.225 - 223.14.3.238	223.14.3.239	255.255.255.240
223.14.3.240	223.14.3.241 - 223.14.3.254	223.14.3.255	255.255.255.240

223.14.3.0/28

IIIIIIII IIIIIIII IIIIIIII IIII/IIII

Network = 2^4 = 16 networks

Hoat = 2^4 = 16 - 2 = 14 hosts